(1) It was calculated That 75 men could complete a piece of a work in 20 days .when work was scheduled to commence, it was found necessary to send 25 men to another project,How much longer will it take to complete the work?
Ans.30days.
Explanation:-
Before
One day work =1/20
One mansone day work=1/(20*75)
Now
No. of workers=50
One day wqrk=50*1/(20*75)
The total no.of days require to complete the work=(75*20)/50=30.
(2) A student divided a number by 2/3 when he required to multiply by 3/2. calculate
the percentage of error in his result.
Ans.0
Explanation:-
Since 3x/2=x/2/3.
(3) A dishonest shopkeeper professes to sell pulses at the cost price,but he uses a false weigh of 950grm.for a kg.His gain is________%.
Ans.5.3
Explanation:-
He sells 950gms of pulses and gains 50grams.if he sells 100 grams of pulses then he will gain(50/950)*100=5.26.
(4) a software engineer has the capacity of thinking 100lines of code in five minutes and can type 100lines of code in 10minutes.He takes a break for five minutes after every ten minutes.How many lines of codes will he complete typing after an hour.
Ans.250lines.
(5) A man was engaged on a job for 30days on the condition.That he would get a wage of Rs.10 for the day he works but he have to pay a fine of Rs.2 for each day of his abience .If he gets Rs.216 at the end, he was absent for work for ---days
Ans.7days
Explanation:-
The equation portraying the given problemis
10*x-2*(30-x)=216
Where x is the number of working days.solving this we get x=23
Numberofdays he was absent was=7(30-23)days.
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